树结构操作
代码笔记大约 2 分钟
树结构操作
遍历树结构
树结构
let tree = [
{
id: '1',
title: '节点1',
children: [
{
id: '1-1',
title: '节点1-1'
},
{
id: '1-2',
title: '节点1-2'
}
]
},
{
id: '2',
title: '节点2',
children: [
{
id: '2-1',
title: '节点2-1'
}
]
}
]
广度优先遍历
function treeForeach(tree, func, childrenName = 'children') {
let node,
list = [...tree]
while ((node = list.shift())) {
func(node)
node[childrenName] && list.push(...node[childrenName])
}
}
深度优先遍历
先序遍历
function treeForeach(tree, func) {
tree.forEach((data) => {
func(data)
data.children && treeForeach(data.children, func) // 遍历子树
})
}
后序遍历
function treeForeach(tree, func) {
tree.forEach((data) => {
data.children && treeForeach(data.children, func) // 遍历子树
func(data)
})
}
深度优先循环
先序遍历
function treeForeach(tree, func) {
let node,
list = [...tree]
while ((node = list.shift())) {
func(node)
node.children && list.unshift(...node.children)
}
}
后序遍历
function treeForeach(tree, func) {
let node,
list = [...tree],
i = 0
while ((node = list[i])) {
let childCount = node.children ? node.children.length : 0
if (!childCount || node.children[childCount - 1] === list[i - 1]) {
func(node)
i++
} else {
list.splice(i, 0, ...node.children)
}
}
}
列表和树结构相互转换
列表转为树
list 数据
let list = [
{
id: '1',
title: '节点1',
parentId: ''
},
{
id: '1-1',
title: '节点1-1',
parentId: '1'
},
{
id: '1-2',
title: '节点1-2',
parentId: '1'
},
{
id: '2',
title: '节点2',
parentId: ''
},
{
id: '2-1',
title: '节点2-1',
parentId: '2'
}
]
function listToTree(list) {
let info = list.reduce(
(map, node) => ((map[node.id] = node), (node.children = []), map),
{}
)
return list.filter((node) => {
info[node.parentId] && info[node.parentId].children.push(node)
return !node.parentId
})
}
树结构转列表
递归实现
function treeToList(tree, result = [], level = 0) {
tree.forEach((node) => {
result.push(node)
node.level = level + 1
node.children && treeToList(node.children, result, level + 1)
})
return result
}
循环实现
function treeToList(tree) {
let node,
result = tree.map((node) => ((node.level = 1), node))
for (let i = 0; i < result.length; i++) {
if (!result[i].children) continue
let list = result[i].children.map(
(node) => ((node.level = result[i].level + 1), node)
)
result.splice(i + 1, 0, ...list)
}
return result
}
树结构筛选
function treeFilter(tree, func) {
// 使用map复制一下节点,避免修改到原树
return tree
.map((node) => ({ ...node }))
.filter((node) => {
node.children = node.children && treeFilter(node.children, func)
return func(node) || (node.children && node.children.length)
})
}
树结构查找
查找节点
function treeFind(tree, func) {
for (const data of tree) {
if (func(data)) return data
if (data.children) {
const res = treeFind(data.children, func)
if (res) return res
}
}
return null
}
查找节点路径
function treeFindPath(tree, func, path = []) {
if (!tree) return []
for (const data of tree) {
path.push(data.id)
if (func(data)) return path
if (data.children) {
const findChildren = treeFindPath(data.children, func, path)
if (findChildren.length) return findChildren
}
path.pop()
}
return []
}
查找多条节点路径
function treeFindPath(tree, func, path = [], result = []) {
for (const data of tree) {
path.push(data.id)
func(data) && result.push([...path])
data.children && treeFindPath(data.children, func, path, result)
path.pop()
}
return result
}